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## Homework Statement

In the figure, a wheel of radius 0.42 m is mounted on a frictionless horizontal axle. A massless cord is wrapped around the wheel and attached to a 2.7 kg box that slides on a frictionless surface inclined at angle

*θ*= 28 owith the horizontal. The box accelerates down the surface at 1.9 m/s2. What is the rotational inertia of the wheel about the axle?

Diagram attached

## Homework Equations

Torque=Moment of Inertia*angular acceleration

F=ma

a=angular acceleration*radius

## The Attempt at a Solution

what i did was combinr the equations and yielded the following

I=(F*r^2)/a=0.47628

I don't see where I did wrong but the solution does not match